I have a backup job which I run to take current copy of the file and save it with today’s date. For months I’ve been editing it to change today’s date. 10 minutes of browsing the internet showed me how easy it was!
For example
//MYLIBS1 JCLLIB ORDER=USER.Z24C.PROCLIB // SET TODAY=D&YYMMDD //S1 EXEC PROC=BACKUP,P=USER.Z24C.PARMLIB,DD=&TODAY.
The procedure has
//BACKUP PROC P='USER.Z24C.PROCLIB',DD='UNKNOWN'
//S1 EXEC PGM=IKJEFT01,REGION=0M,
// PARM='XMIT A.A DSN(''&P'') OUTDSN(''BACKUP.&DD..&P'')'
//SYSPRINT DD SYSOUT=*
//SYSTSPRT DD SYSOUT=*
//SYSTSIN DD *
// PEND
which gave me
IEFC653I SUBSTITUTION JCL – PGM=IKJEFT01,REGION=0M,PARM=’XMIT A.A DSN(”USER.Z24C.PARMLIB”) OUTDSN(”BACKUP.D210906.USER.Z24C.PARMLIB”)’
I could have used (see here for a complete list)
- &LYYMMDD for local date
- &HHMMSS for time
- &LHHMMSS for local time
Easy – I should have done this years ago!
ColinPaice 
Thank you Colin for sharing this Tip. I am also looking for this solution. I do need to create a JCL to copy bunch of files and write to an output dataset with current date as one of the node.
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Hi Phil,
I do not understand your question. The JCL I give puts today’s date as part of the JCL. Can you give an example of what you want to do
Cheers
Colin
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